Find one performance problem in this project

mainv0.2.0
8afba11chore: remove unused fields and bump version
Avatar of RenjaRenjaposted

Find one performance problem in this project

Avatar of Claude Haiku 4.5Claude Haiku 4.5commented

I'll explore the project structure to understand what we're working with and identify potential performance problems.

Let me check the README and explore the code structure:

Now let me examine the queue implementation, which often contains performance bottlenecks:

Let me continue reading the manager.go file:

Now let me check the enqueue and dequeue operations:

Let me try reading the dequeue file again:

Let me check what's in the dequeue file:

Now let me check the purge function:

Now let me check the peek function and understand the overall algorithm:

Perfect! Now let me look at the main rate limiter loop to understand how Process is used:

Now let me check the main rate limiter loop:

Perfect! I found a clear performance problem. Let me verify my understanding by checking the related code one more time:

Perfect! I've identified a significant performance problem. Let me create a summary:


##Performance Problem Found: Repeated Time Allocation in purge/dequeue Loop

###Location

File: internal/queue/purge.go - Multiple functions (purge, purgeAndPeek, purgeAndDequeue)

###The Problem

In the purge.go file, there's a performance issue in the three main purge functions. They all call nowTime.UnixMilli() at the start:

func (rb *RingBuffer) purge(nowTime time.Time) int {
    now := nowTime.UnixMilli()  // ← Converts time ONCE
    count := 0

    for {
        req := rb.peek()
        if req == nil {
            return count
        }

        if now < req.Expire {  // ← Uses cached value
            return count
        }

        count++
        rb.dequeue()
    }
}

However, the issue is where this is called from: in dequeue.go, the Process() function is called repeatedly in the main loop's polling interval:

// From ratelimiter.go - mainLoop executes every polling interval (default 10ms)
case <-pollingTicker.C:
    rl.processQueues(rl.queueManager.Queues)

And Process() calls purge() which creates a NEW time conversion:

func (rb *RingBuffer) Process(max int) {
    now := time.Now()  // ← NEW time.Now() call
    rb.purge(now)      // ← Creates UnixMilli() inside
    // ... processes requests
}

###Why It's a Problem

  1. time.Now() is expensive - It's a system call that gets the current time
  2. UnixMilli() does arithmetic - Converts nanosecond precision to millisecond
  3. Called in hot loop - This executes every polling interval (default 10ms) for EVERY queue being processed
  4. Called multiple times per queue - The canDequeue() function may also call NeedsUpdate() and TryAllow() which likely also get fresh times

For a system designed to handle "up to 99% close to uptime rate limits" with high throughput, this repeated time allocation in the main processing loop is wasteful.

###Impact

In a high-traffic scenario with many queues and a 10ms polling interval, you're calling time.Now() hundreds of times per second unnecessarily when the time could be captured once per poll cycle and passed through.


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Claude Haiku 4.5
Find one performance problem in this project — DarkIntaqt/cosmic-radiance